Stefan Boltzmann Law Calculator

In this Stefan-Boltzmann Law guide, we will show you how to calculate the total radiated power of an object in a matter of seconds.

We will also help you understand the Stefan-Boltzmann law, its formula, and what each variable means while we’re at it.

What is the Stefan-Boltzmann Law?

Why does temperature and surface area affect the radiation of an object? H

ow to apply this law in real-world situations? Find all the answers here!

Stefan-Boltzmann Law Calculator

Calculate the total radiated power of an object using P = ε σ A T⁴

Stefan-Boltzmann Law: Formula Explanation

The Stefan-Boltzmann Law describes how much power (P) an object radiates based on its surface area (A), temperature (T), and emissivity (ε). The formula is:

P = ε σ A T⁴

  • P: Total Radiated Power (Watts, W)
  • A: Surface Area of the object (m²)
  • ε: Emissivity of the material (0 to 1)
  • σ: Stefan-Boltzmann Constant (5.670374419 × 10⁻⁸ W/m²·K⁴)
  • T: Temperature in Kelvin (K)

Real-World Applications

Solar Panels

Used to calculate the thermal radiation emitted by the panel at high temperatures.

Astrophysics

Determines the luminosity of stars based on their surface temperature and size.

Industrial Heating

Used to estimate heat loss from furnaces or radiators to optimize efficiency.

Solved Example: Step-by-Step

Problem: Calculate the total radiated power of an object with surface area 2 m², emissivity 0.8, and temperature 500 K.

Step 1: Identify known values:
A = 2 m², ε = 0.8, T = 500 K, σ = 5.670374419 × 10⁻⁸ W/m²·K⁴
Step 2: Write the Stefan-Boltzmann formula:
P = ε × σ × A × T⁴
Step 3: Substitute the known values:
P = 0.8 × (5.670374419 × 10⁻⁸) × 2 × (500)⁴
Step 4: Calculate T⁴:
500⁴ = 62,500,000,000
Step 5: Multiply all values:
P = 0.8 × 5.670374419 × 10⁻⁸ × 2 × 62,500,000,000
P ≈ 5663.5 W
Step 6: Conclusion:
The object radiates approximately 5663.5 Watts of power.

Reference Table: Stefan-Boltzmann Law

VariableMeaningTypical Values / Notes
PTotal Radiated PowerWatts (W)
ASurface Area of Objectm² (e.g., 1 – 10 m²)
εEmissivity of Material0 – 1 (0 = perfect reflector, 1 = perfect emitter)
σStefan-Boltzmann Constant5.670374419 × 10⁻⁸ W/m²·K⁴
TTemperatureKelvin (K), e.g., 300 K – 6000 K
ApplicationsWhere the formula is usefulAstrophysics, Solar Panels, Industrial Heating

FAQs

What is the Stefan-Boltzmann Law?

In simple words, it tells us how much power an object radiates based on its temperature, surface area, and material.

What does emissivity mean?

Emissivity (ε) shows how good a material is at radiating heat. It ranges from 0 (no radiation) to 1 (perfect radiator).

Why is this law important?

It helps us understand how objects like stars, furnaces, and solar panels emit heat or light based on temperature.

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